36w-w^2=0

Solution for 36w-w^2=0 equation:

36w-w^2=0

We add all the numbers together, and all the variables

-1w^2+36w=0

a = -1; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-1)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-1}=\frac{-72}{-2}
=+36
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-1}=\frac{0}{-2}
=0
$